What are the solutions to the equation 5x^2=40 ?

The solutions to the equation 5x^2=40 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 5x^2=40

The zeros of 5x^2=40 are x=2sqrt(2),x=-2sqrt(2)

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5 x^{2} = 40

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

5 x^{2} = 40

Divide both sides by

5

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

10 x^{3} - 8 x^{2} + 25 x - 20

∣ 3 \cdot (x + 2) ∣ + 6 = 24

3 m^{2} - 9 = 0

∣ 6 x - 1 ∣ + 3 = 19

5 x + 1 = 3 x + 1

What are the solutions to the equation 5x^2=40 ?
The solutions to the equation 5x^2=40 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 5x^2=40
The zeros of 5x^2=40 are x=2sqrt(2),x=-2sqrt(2)