What is factor n^2-13n+40 ?

The solution to factor n^2-13n+40 is (n-5)(n-8)

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factor n^2-13n+40

factor

n^{2} - 13 n + 40

(n - 5) (n - 8)

Solution steps

n^{2} - 13 n + 40

Break the expression into groups

= (n^{2} - 5 n) + (- 8 n + 40)

Factor out

n

from

n^{2} - 5 n : n (n - 5)

Factor out

- 8

from

- 8 n + 40 : - 8 (n - 5)

= n (n - 5) - 8 (n - 5)

Factor out common term

n - 5

= (n - 5) (n - 8)

9 + \frac{x}{5} - 2 = 4.8

(x - 5) (x + 3) \leq 0

18 x + 27 - 42 x - 12 = - 81

- \frac{5}{9} - (- \frac{1}{15})

\frac{3}{5} + \frac{1}{10}