What are the solutions to the equation m^2+4m-1=0 ?

The solutions to the equation m^2+4m-1=0 are m=-2+sqrt(5),m=-2-sqrt(5)

Find the zeros of m^2+4m-1=0

The zeros of m^2+4m-1=0 are m=-2+sqrt(5),m=-2-sqrt(5)

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m^{2} + 4 m - 1 = 0

m = - 2 + 5, m = - 2 - 5

Decimal Notation

m = 0.23606 \dots, m = - 4.23606 \dots

Solution steps

m^{2} + 4 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 1) = 25

m_{1, 2} = \frac{- 4 \pm 2 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 5}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 5}{2 \cdot 1}

m = \frac{- 4 + 2 5}{2 \cdot 1} : - 2 + 5

m = \frac{- 4 - 2 5}{2 \cdot 1} : - 2 - 5

The solutions to the quadratic equation are:

m = - 2 + 5, m = - 2 - 5

\frac{\frac{- 3}{2}}{2}

5 n^{3} - 10 n^{2} + 3 n - 6

- 147

48 + 2 k = k^{2}

x^{2} + 26 x + 168

What are the solutions to the equation m^2+4m-1=0 ?
The solutions to the equation m^2+4m-1=0 are m=-2+sqrt(5),m=-2-sqrt(5)
Find the zeros of m^2+4m-1=0
The zeros of m^2+4m-1=0 are m=-2+sqrt(5),m=-2-sqrt(5)