What are the solutions to the equation 6x^2+6x+1=0 ?

The solutions to the equation 6x^2+6x+1=0 are x=(-3+sqrt(3))/6 ,x=-(sqrt(3)+1)/(2sqrt(3))

Find the zeros of 6x^2+6x+1=0

The zeros of 6x^2+6x+1=0 are x=(-3+sqrt(3))/6 ,x=-(sqrt(3)+1)/(2sqrt(3))

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6 x^{2} + 6 x + 1 = 0

x = \frac{- 3 + 3}{6}, x = - \frac{3 + 1}{2 3}

Decimal Notation

x = - 0.21132 \dots, x = - 0.78867 \dots

Solution steps

6 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

6^{2} - 4 \cdot 6 \cdot 1 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 6}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 6}

x = \frac{- 6 + 2 3}{2 \cdot 6} : \frac{- 3 + 3}{6}

x = \frac{- 6 - 2 3}{2 \cdot 6} : - \frac{3 + 1}{2 3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3}{6}, x = - \frac{3 + 1}{2 3}

lo g_{2} (0.25)

31 - 3 x = 3 x - 19

- 2 m + 3 = - 2 - m

2 \cdot 25

- 3 x + 4 \geq - 23

What are the solutions to the equation 6x^2+6x+1=0 ?
The solutions to the equation 6x^2+6x+1=0 are x=(-3+sqrt(3))/6 ,x=-(sqrt(3)+1)/(2sqrt(3))
Find the zeros of 6x^2+6x+1=0
The zeros of 6x^2+6x+1=0 are x=(-3+sqrt(3))/6 ,x=-(sqrt(3)+1)/(2sqrt(3))