What are the solutions to the equation w^2+14w-1800=0 ?

The solutions to the equation w^2+14w-1800=0 are w=36,w=-50

Find the zeros of w^2+14w-1800=0

The zeros of w^2+14w-1800=0 are w=36,w=-50

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w^{2} + 14 w - 1800 = 0

w = 36, w = - 50

Solution steps

w^{2} + 14 w - 1800 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 1800 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 1800) = 86

w_{1, 2} = \frac{- 14 \pm 86}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 14 + 86}{2 \cdot 1}, w_{2} = \frac{- 14 - 86}{2 \cdot 1}

w = \frac{- 14 + 86}{2 \cdot 1} : 36

w = \frac{- 14 - 86}{2 \cdot 1} : - 50

The solutions to the quadratic equation are:

w = 36, w = - 50

(2 x - 5)^{2} = 49

5^{∣ x ∣} = 5

2 r^{2} + 7 r - 30

- \frac{3}{4} - \frac{1}{2}

4 ∣ x - 8 ∣ - 8 = - 5 ∣ x - 8 ∣ + 19

What are the solutions to the equation w^2+14w-1800=0 ?
The solutions to the equation w^2+14w-1800=0 are w=36,w=-50
Find the zeros of w^2+14w-1800=0
The zeros of w^2+14w-1800=0 are w=36,w=-50