What are the solutions to the equation x^2+3x+127=2 ?

The solutions to the equation x^2+3x+127=2 are x=-3/2+i(sqrt(491))/2 ,x=-3/2-i(sqrt(491))/2

Find the zeros of x^2+3x+127=2

The zeros of x^2+3x+127=2 are x=-3/2+i(sqrt(491))/2 ,x=-3/2-i(sqrt(491))/2

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x^{2} + 3 x + 127 = 2

x = - \frac{3}{2} + i \frac{491}{2}, x = - \frac{3}{2} - i \frac{491}{2}

Solution steps

x^{2} + 3 x + 127 = 2

Move

2

to the left side

x^{2} + 3 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 125}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 125 : 491 i

x_{1, 2} = \frac{- 3 \pm 491 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 491 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 491 i}{2 \cdot 1}

x = \frac{- 3 + 491 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{491}{2}

x = \frac{- 3 - 491 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{491}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{491}{2}, x = - \frac{3}{2} - i \frac{491}{2}

\frac{x + 4}{x - 2} - \frac{x + 3}{x - 5} > 0

\frac{∣ 237.4 - x ∣}{237.4} = 0.05

\frac{5 !}{( 5 - 2 ) ! 2 !}

\frac{X - 3}{X + 2} > 0

x - 0 = 6

What are the solutions to the equation x^2+3x+127=2 ?
The solutions to the equation x^2+3x+127=2 are x=-3/2+i(sqrt(491))/2 ,x=-3/2-i(sqrt(491))/2
Find the zeros of x^2+3x+127=2
The zeros of x^2+3x+127=2 are x=-3/2+i(sqrt(491))/2 ,x=-3/2-i(sqrt(491))/2