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Popular >

|(x-1)/(x+1)|>= 1

Solution

\frac{x - 1}{x + 1} \geq 1

Solution

x < - 1 or - 1 < x \leq 0

+1

Interval Notation

(- \infty, - 1) \cup (- 1, 0]

Solution steps

\frac{x - 1}{x + 1} \geq 1

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

\frac{x - 1}{x + 1} \leq - 1 or \frac{x - 1}{x + 1} \geq 1

\frac{x - 1}{x + 1} \leq - 1 or \frac{x - 1}{x + 1} \geq 1

x < - 1 or - 1 < x \leq 0

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Frequently Asked Questions (FAQ)

What is |(x-1)/(x+1)|>= 1 ?
The solution to |(x-1)/(x+1)|>= 1 is x<-1\lor-1<x<= 0