What are the solutions to the equation 9x^2+21x-8=0 ?

The solutions to the equation 9x^2+21x-8=0 are x= 1/3 ,x=-8/3

Find the zeros of 9x^2+21x-8=0

The zeros of 9x^2+21x-8=0 are x= 1/3 ,x=-8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} + 21 x - 8 = 0

x = \frac{1}{3}, x = - \frac{8}{3}

Decimal Notation

x = 0.33333 \dots, x = - 2.66666 \dots

Solution steps

9 x^{2} + 21 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

2 1^{2} - 4 \cdot 9 (- 8) = 27

x_{1, 2} = \frac{- 21 \pm 27}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 21 + 27}{2 \cdot 9}, x_{2} = \frac{- 21 - 27}{2 \cdot 9}

x = \frac{- 21 + 27}{2 \cdot 9} : \frac{1}{3}

x = \frac{- 21 - 27}{2 \cdot 9} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{8}{3}

5 x - 19 \leq 1

u^{2} - 6 u - 7

7 w + 4 - 3 w = 15

s^{2} + 10 s + 21 = 0

\frac{( \frac{1}{2} ) ^{2}}{2}

What are the solutions to the equation 9x^2+21x-8=0 ?
The solutions to the equation 9x^2+21x-8=0 are x= 1/3 ,x=-8/3
Find the zeros of 9x^2+21x-8=0
The zeros of 9x^2+21x-8=0 are x= 1/3 ,x=-8/3