What are the solutions to the equation 4x^2-12x-7=0 ?

The solutions to the equation 4x^2-12x-7=0 are x= 7/2 ,x=-1/2

Find the zeros of 4x^2-12x-7=0

The zeros of 4x^2-12x-7=0 are x= 7/2 ,x=-1/2

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4 x^{2} - 12 x - 7 = 0

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

4 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 4}

x = \frac{- ( - 12 ) + 16}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 12 ) - 16}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

3 (x - 2) = 9

- \frac{3}{4} ∣ x + 5 ∣ + \frac{5}{2} = 1

- 22 < t - 3 - 1

(\frac{x ^{2}}{9})^{2}

\frac{\frac{1}{( x + h ) ^{3}} - \frac{1}{x ^{3}}}{h}

What are the solutions to the equation 4x^2-12x-7=0 ?
The solutions to the equation 4x^2-12x-7=0 are x= 7/2 ,x=-1/2
Find the zeros of 4x^2-12x-7=0
The zeros of 4x^2-12x-7=0 are x= 7/2 ,x=-1/2