What are the solutions to the equation x^2-14x+41=0 ?

The solutions to the equation x^2-14x+41=0 are x=7+2sqrt(2),x=7-2sqrt(2)

Find the zeros of x^2-14x+41=0

The zeros of x^2-14x+41=0 are x=7+2sqrt(2),x=7-2sqrt(2)

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x^{2} - 14 x + 41 = 0

x = 7 + 22, x = 7 - 22

Decimal Notation

x = 9.82842 \dots, x = 4.17157 \dots

Solution steps

x^{2} - 14 x + 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 41}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 41 = 42

x_{1, 2} = \frac{- ( - 14 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4 2}{2 \cdot 1} : 7 + 22

x = \frac{- ( - 14 ) - 4 2}{2 \cdot 1} : 7 - 22

The solutions to the quadratic equation are:

x = 7 + 22, x = 7 - 22

\frac{- 21 \cdot - 3}{7}

x^{2} + 3 x - 54 = 0

\frac{\frac{1}{10}}{2}

9^{3}

3 x^{2} - 3 x - 9

What are the solutions to the equation x^2-14x+41=0 ?
The solutions to the equation x^2-14x+41=0 are x=7+2sqrt(2),x=7-2sqrt(2)
Find the zeros of x^2-14x+41=0
The zeros of x^2-14x+41=0 are x=7+2sqrt(2),x=7-2sqrt(2)