What are the solutions to the equation -27+(12-x)^2=-22 ?

The solutions to the equation -27+(12-x)^2=-22 are x=12-sqrt(5),x=12+sqrt(5)

Find the zeros of -27+(12-x)^2=-22

The zeros of -27+(12-x)^2=-22 are x=12-sqrt(5),x=12+sqrt(5)

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- 27 + (12 - x)^{2} = - 22

x = 12 - 5, x = 12 + 5

Decimal Notation

x = 9.76393 \dots, x = 14.23606 \dots

Solution steps

- 27 + (12 - x)^{2} = - 22

Move

27

to the right side

(12 - x)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

12 - x = 5 : x = 12 - 5

Solve

12 - x = - 5 : x = 12 + 5

The solutions to the quadratic equation are:

x = 12 - 5, x = 12 + 5

a^{7} + a^{6} b + a^{5} b^{2} + a^{4} b^{3} + a^{3} b^{4} + a^{2} b^{5} + a b^{6} + b^{7}

\frac{2}{2 ^{- 3}}

\frac{5 !}{2 ! \cdot 3 !}

x + 2 = 4 x + 8

x^{2} + 5 x = 14

What are the solutions to the equation -27+(12-x)^2=-22 ?
The solutions to the equation -27+(12-x)^2=-22 are x=12-sqrt(5),x=12+sqrt(5)
Find the zeros of -27+(12-x)^2=-22
The zeros of -27+(12-x)^2=-22 are x=12-sqrt(5),x=12+sqrt(5)