What are the solutions to the equation 25x^2+9=0 ?

The solutions to the equation 25x^2+9=0 are x= 3/5 i,x=-3/5 i

Find the zeros of 25x^2+9=0

The zeros of 25x^2+9=0 are x= 3/5 i,x=-3/5 i

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25 x^{2} + 9 = 0

x = \frac{3}{5} i, x = - \frac{3}{5} i

Solution steps

25 x^{2} + 9 = 0

Move

9

to the right side

25 x^{2} = - 9

Divide both sides by

25

x^{2} = - \frac{9}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{9}{25}, x = - - \frac{9}{25}

- \frac{9}{25} = \frac{3}{5} i

- - \frac{9}{25} = - \frac{3}{5} i

x = \frac{3}{5} i, x = - \frac{3}{5} i

1 - \frac{X}{3} + \frac{1}{5} = \frac{7}{10}

- 2 \leq 12 - 3 x \leq 5

- 1 < 2 - m

2 ∣ 2 x - 7 ∣ + 2 > 16

12 = - 2.7 t^{2} + 40 t + 6.5

What are the solutions to the equation 25x^2+9=0 ?
The solutions to the equation 25x^2+9=0 are x= 3/5 i,x=-3/5 i
Find the zeros of 25x^2+9=0
The zeros of 25x^2+9=0 are x= 3/5 i,x=-3/5 i