What is |2s+1|+3<= 2 ?

The solution to |2s+1|+3<= 2 is No Solution for s\in\mathbb{R}

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|2s+1|+3<= 2

∣ 2 s + 1 ∣ + 3 \leq 2

No Solution for s \in R

Solution steps

∣ 2 s + 1 ∣ + 3 \leq 2

Move

3

to the right side

∣ 2 s + 1 ∣ \leq - 1

Absolute value cannot be less than 0

No Solution for s \in R

3 x (5 x + 2) = 0

2 x^{5} + 2 x^{2} 2 y^{3} - 8 x^{3} - 8 y^{3}

5^{4} \cdot 5^{- 2}

lo g_{\frac{1}{5}} (2)

2 x - 7 \geq 13

What is |2s+1|+3<= 2 ?
The solution to |2s+1|+3<= 2 is No Solution for s\in\mathbb{R}