What are the solutions to the equation 7x^2+7x-6=0 ?

The solutions to the equation 7x^2+7x-6=0 are x=(-7+sqrt(217))/(14),x=(-7-sqrt(217))/(14)

Find the zeros of 7x^2+7x-6=0

The zeros of 7x^2+7x-6=0 are x=(-7+sqrt(217))/(14),x=(-7-sqrt(217))/(14)

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7 x^{2} + 7 x - 6 = 0

x = \frac{- 7 + 217}{14}, x = \frac{- 7 - 217}{14}

Decimal Notation

x = 0.55220 \dots, x = - 1.55220 \dots

Solution steps

7 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

7^{2} - 4 \cdot 7 (- 6) = 217

x_{1, 2} = \frac{- 7 \pm 217}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 7 + 217}{2 \cdot 7}, x_{2} = \frac{- 7 - 217}{2 \cdot 7}

x = \frac{- 7 + 217}{2 \cdot 7} : \frac{- 7 + 217}{14}

x = \frac{- 7 - 217}{2 \cdot 7} : \frac{- 7 - 217}{14}

The solutions to the quadratic equation are:

x = \frac{- 7 + 217}{14}, x = \frac{- 7 - 217}{14}

9 y (2 y + 7) + (2 y + 7)

6 4^{- \frac{3}{2}}

9 (t + 1) - 6 (t + 1) = 5 t + 9

- 7 x > 28

y - 3 \geq - 13 and y + 2 \leq 8

What are the solutions to the equation 7x^2+7x-6=0 ?
The solutions to the equation 7x^2+7x-6=0 are x=(-7+sqrt(217))/(14),x=(-7-sqrt(217))/(14)
Find the zeros of 7x^2+7x-6=0
The zeros of 7x^2+7x-6=0 are x=(-7+sqrt(217))/(14),x=(-7-sqrt(217))/(14)