What are the solutions to the equation x^2-24x+144=100 ?

The solutions to the equation x^2-24x+144=100 are x=22,x=2

Find the zeros of x^2-24x+144=100

The zeros of x^2-24x+144=100 are x=22,x=2

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x^{2} - 24 x + 144 = 100

x = 22, x = 2

Solution steps

x^{2} - 24 x + 144 = 100

Move

100

to the left side

x^{2} - 24 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 44 = 20

x_{1, 2} = \frac{- ( - 24 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 20}{2 \cdot 1}

x = \frac{- ( - 24 ) + 20}{2 \cdot 1} : 22

x = \frac{- ( - 24 ) - 20}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 22, x = 2

\frac{3}{4} \cdot \frac{5}{2}

x^{4} - 4 x^{2} + 3 = 0

5 u^{2} = 15 u

\frac{4}{7} \cdot 14

\frac{3 ^{3}}{3}

What are the solutions to the equation x^2-24x+144=100 ?
The solutions to the equation x^2-24x+144=100 are x=22,x=2
Find the zeros of x^2-24x+144=100
The zeros of x^2-24x+144=100 are x=22,x=2