What is factor 16x^4-81y^4 ?

The solution to factor 16x^4-81y^4 is (4x^2+9y^2)(2x+3y)(2x-3y)

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factor 16x^4-81y^4

factor

16 x^{4} - 81 y^{4}

(4 x^{2} + 9 y^{2}) (2 x + 3 y) (2 x - 3 y)

Solution steps

16 x^{4} - 81 y^{4}

16 x^{4} = (4 x^{2})^{2}

81 y^{4} = (9 y^{2})^{2}

= (4 x^{2})^{2} - (9 y^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 x^{2})^{2} - (9 y^{2})^{2} = (4 x^{2} + 9 y^{2}) (4 x^{2} - 9 y^{2})

= (4 x^{2} + 9 y^{2}) (4 x^{2} - 9 y^{2})

Factor

4 x^{2} - 9 y^{2} : (2 x + 3 y) (2 x - 3 y)

= (4 x^{2} + 9 y^{2}) (2 x + 3 y) (2 x - 3 y)

2 w^{2} + 7 w + 5

\frac{2}{5} \cdot \frac{1}{3}

\frac{29}{100} = \frac{x}{263344.82}

\frac{10 \cdot 2300}{142506}

50 x^{2} - 32

What is factor 16x^4-81y^4 ?
The solution to factor 16x^4-81y^4 is (4x^2+9y^2)(2x+3y)(2x-3y)