What are the solutions to the equation x^2+3/4 =0 ?

The solutions to the equation x^2+3/4 =0 are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i

Find the zeros of x^2+3/4 =0

The zeros of x^2+3/4 =0 are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i

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x^{2} + \frac{3}{4} = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

x^{2} + \frac{3}{4} = 0

Move

\frac{3}{4}

to the right side

x^{2} = - \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{4}, x = - - \frac{3}{4}

- \frac{3}{4} = \frac{3}{2} i

- - \frac{3}{4} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

\frac{3}{8} (2 x - 3) - \frac{4}{3} (x - 2) = \frac{2}{3}

2 x^{2} + x - 1 = 2 x + 1

\frac{5 !}{1 ! ( 5 - 1 ) !}

4 p \geq - 28

x^{2} - 11 x + 32 = 0

What are the solutions to the equation x^2+3/4 =0 ?
The solutions to the equation x^2+3/4 =0 are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i
Find the zeros of x^2+3/4 =0
The zeros of x^2+3/4 =0 are x=(sqrt(3))/2 i,x=-(sqrt(3))/2 i