What are the solutions to the equation 3x^2+5x=4 ?

The solutions to the equation 3x^2+5x=4 are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6

Find the zeros of 3x^2+5x=4

The zeros of 3x^2+5x=4 are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6

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3 x^{2} + 5 x = 4

x = \frac{- 5 + 73}{6}, x = \frac{- 5 - 73}{6}

Decimal Notation

x = 0.59066 \dots, x = - 2.25733 \dots

Solution steps

3 x^{2} + 5 x = 4

Move

4

to the left side

3 x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 4) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 3}, x_{2} = \frac{- 5 - 73}{2 \cdot 3}

x = \frac{- 5 + 73}{2 \cdot 3} : \frac{- 5 + 73}{6}

x = \frac{- 5 - 73}{2 \cdot 3} : \frac{- 5 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{6}, x = \frac{- 5 - 73}{6}

6 - x = x^{2}

x^{2} - 10 x + 25 = 35

d - 5 < 1

∣ 2 x - 1 ∣ - 7 = - 2

12 x^{2} - 30 x + 6

What are the solutions to the equation 3x^2+5x=4 ?
The solutions to the equation 3x^2+5x=4 are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6
Find the zeros of 3x^2+5x=4
The zeros of 3x^2+5x=4 are x=(-5+sqrt(73))/6 ,x=(-5-sqrt(73))/6