What are the solutions to the equation r^2+6r+5=0 ?

The solutions to the equation r^2+6r+5=0 are r=-1,r=-5

Find the zeros of r^2+6r+5=0

The zeros of r^2+6r+5=0 are r=-1,r=-5

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r^{2} + 6 r + 5 = 0

r = - 1, r = - 5

Solution steps

r^{2} + 6 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

r_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 6 + 4}{2 \cdot 1}, r_{2} = \frac{- 6 - 4}{2 \cdot 1}

r = \frac{- 6 + 4}{2 \cdot 1} : - 1

r = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

r = - 1, r = - 5

- \frac{1}{5} (5)

\frac{1}{4} k = 3 (- \frac{1}{4} k + 3)

\frac{30}{4}

\frac{63 x ^{2} y ^{2}}{42 x ^{6} y ^{4}}

5 x + 14 - 7 x = - 20

What are the solutions to the equation r^2+6r+5=0 ?
The solutions to the equation r^2+6r+5=0 are r=-1,r=-5
Find the zeros of r^2+6r+5=0
The zeros of r^2+6r+5=0 are r=-1,r=-5