What are the solutions to the equation 2m^2+10=210 ?

The solutions to the equation 2m^2+10=210 are m=10,m=-10

Find the zeros of 2m^2+10=210

The zeros of 2m^2+10=210 are m=10,m=-10

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2 m^{2} + 10 = 210

m = 10, m = - 10

Solution steps

2 m^{2} + 10 = 210

Move

10

to the right side

2 m^{2} = 200

Divide both sides by

2

m^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 100, m = - 100

100 = 10

- 100 = - 10

m = 10, m = - 10

\frac{3 + i 3}{3 - i 3}

- 1 \leq \frac{2 x - 3}{2} < 4

- 21 x - 6 x^{2}

- 3 ∣ x + 9 ∣ + 2 = 10 ∣ x + 9 ∣ + 5

\frac{- 4 - 5}{8 - 2}

What are the solutions to the equation 2m^2+10=210 ?
The solutions to the equation 2m^2+10=210 are m=10,m=-10
Find the zeros of 2m^2+10=210
The zeros of 2m^2+10=210 are m=10,m=-10