What are the solutions to the equation (w+5)^2-72=0 ?

The solutions to the equation (w+5)^2-72=0 are w=6sqrt(2)-5,w=-6sqrt(2)-5

Find the zeros of (w+5)^2-72=0

The zeros of (w+5)^2-72=0 are w=6sqrt(2)-5,w=-6sqrt(2)-5

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(w + 5)^{2} - 72 = 0

w = 62 - 5, w = - 62 - 5

Decimal Notation

w = 3.48528 \dots, w = - 13.48528 \dots

Solution steps

(w + 5)^{2} - 72 = 0

Move

72

to the right side

(w + 5)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

w + 5 = 72 : w = 62 - 5

Solve

w + 5 = - 72 : w = - 62 - 5

The solutions to the quadratic equation are:

w = 62 - 5, w = - 62 - 5

\frac{1}{x + 1} + \frac{1}{x + 2} - \frac{4 x}{x ^{2} + 3 x + 2} < 0

2 x^{2} + 12 x + 8 = 8 x + 4

\frac{- 5 + ( 5 ) ^{2} - 4 ( 3 ) ( - 2 )}{2 ( 3 )} = x

3 x + 2 < 2 x - 4

2 r^{2} + 5 r - 3 = 0

What are the solutions to the equation (w+5)^2-72=0 ?
The solutions to the equation (w+5)^2-72=0 are w=6sqrt(2)-5,w=-6sqrt(2)-5
Find the zeros of (w+5)^2-72=0
The zeros of (w+5)^2-72=0 are w=6sqrt(2)-5,w=-6sqrt(2)-5