What is factor 3x^2-16-12 ?

The solution to factor 3x^2-16-12 is (sqrt(3)x+2sqrt(7))(sqrt(3)x-2sqrt(7))

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factor 3x^2-16-12

factor

3 x^{2} - 16 - 12

(3 x + 27) (3 x - 27)

Solution steps

3 x^{2} - 16 - 12

Subtract the numbers:

- 16 - 12 = - 28

= 3 x^{2} - 28

Rewrite

3 x^{2} - 28

(3 x)^{2} - (28)^{2}

= (3 x)^{2} - (28)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(3 x)^{2} - (28)^{2} = (3 x + 28) (3 x - 28)

= (3 x + 28) (3 x - 28)

Refine

= (3 x + 27) (3 x - 27)

6 (\frac{x}{2} + 4) \geq 9

3 x = 3 x

\frac{- x ^{3}}{x ^{4}}

\frac{3}{4} = y - \frac{1}{5} (8)

\frac{b - 8}{- 2} = 11

What is factor 3x^2-16-12 ?
The solution to factor 3x^2-16-12 is (sqrt(3)x+2sqrt(7))(sqrt(3)x-2sqrt(7))