What are the solutions to the equation x^2-9=x+11 ?

The solutions to the equation x^2-9=x+11 are x=5,x=-4

Find the zeros of x^2-9=x+11

The zeros of x^2-9=x+11 are x=5,x=-4

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x^{2} - 9 = x + 11

x = 5, x = - 4

Solution steps

x^{2} - 9 = x + 11

Move

11

to the left side

x^{2} - 20 = x

Move

x

to the left side

x^{2} - 20 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

(- 2)^{5}

\frac{- 40 c ^{9} d ^{4}}{5 c ^{3} d ^{7}}

(\frac{17}{2})^{2}

3 x - 1 \leq 8 x - 16

40 < 20 - 10 x \leq 100

What are the solutions to the equation x^2-9=x+11 ?
The solutions to the equation x^2-9=x+11 are x=5,x=-4
Find the zeros of x^2-9=x+11
The zeros of x^2-9=x+11 are x=5,x=-4