What are the solutions to the equation 4x^2-9x=-3 ?

The solutions to the equation 4x^2-9x=-3 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8

Find the zeros of 4x^2-9x=-3

The zeros of 4x^2-9x=-3 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 9 x = - 3

x = \frac{9 + 33}{8}, x = \frac{9 - 33}{8}

Decimal Notation

x = 1.84307 \dots, x = 0.40692 \dots

Solution steps

4 x^{2} - 9 x = - 3

Move

3

to the left side

4 x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 3 = 33

x_{1, 2} = \frac{- ( - 9 ) \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 33}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 33}{2 \cdot 4}

x = \frac{- ( - 9 ) + 33}{2 \cdot 4} : \frac{9 + 33}{8}

x = \frac{- ( - 9 ) - 33}{2 \cdot 4} : \frac{9 - 33}{8}

The solutions to the quadratic equation are:

x = \frac{9 + 33}{8}, x = \frac{9 - 33}{8}

3 (y + 2) + 2 y = 7 (y - 1) + 9

(125)^{\frac{2}{3}}

10 - 4 \frac{1}{16}

- 13 x + 5 \geq 57

(4 b^{4})^{2}

What are the solutions to the equation 4x^2-9x=-3 ?
The solutions to the equation 4x^2-9x=-3 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8
Find the zeros of 4x^2-9x=-3
The zeros of 4x^2-9x=-3 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8