What are the solutions to the equation 5r^2-45=0 ?

The solutions to the equation 5r^2-45=0 are r=3,r=-3

Find the zeros of 5r^2-45=0

The zeros of 5r^2-45=0 are r=3,r=-3

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5 r^{2} - 45 = 0

r = 3, r = - 3

Solution steps

5 r^{2} - 45 = 0

Move

45

to the right side

5 r^{2} = 45

Divide both sides by

5

r^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 9, r = - 9

9 = 3

- 9 = - 3

r = 3, r = - 3

x^{2} - 36 > 0

- 4 (x + 3) = 16 - 4 x

5 + 6 x = 4 x + 1

2 x - \frac{x - 2}{4} = \frac{5 x}{8} + 5

\frac{b ^{\frac{1}{5}}}{b}

What are the solutions to the equation 5r^2-45=0 ?
The solutions to the equation 5r^2-45=0 are r=3,r=-3
Find the zeros of 5r^2-45=0
The zeros of 5r^2-45=0 are r=3,r=-3