What is ((2x^4y^2)/(4x^2y))^3 ?

The solution to ((2x^4y^2)/(4x^2y))^3 is (x^6y^3)/8

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simplify ((2x^4y^2)/(4x^2y))^3

simplify

(\frac{2 x ^{4} y ^{2}}{4 x ^{2} y})^{3}

\frac{x ^{6} y ^{3}}{8}

Solution steps

(\frac{2 x ^{4} y ^{2}}{4 x ^{2} y})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ^{4} y ^{2} ) ^{3}}{( 4 x ^{2} y ) ^{3}}

Simplify

(2 x^{4} y^{2})^{3} : 8 x^{12} y^{6}

= \frac{8 x ^{12} y ^{6}}{( 4 x ^{2} y ) ^{3}}

Simplify

(4 x^{2} y)^{3} : 64 x^{6} y^{3}

= \frac{8 x ^{12} y ^{6}}{64 x ^{6} y ^{3}}

Cancel the common factor:

8

= \frac{x ^{12} y ^{6}}{8 x ^{6} y ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{12}}{x ^{6}} = x^{12 - 6}

= \frac{y ^{6} x ^{12 - 6}}{8 y ^{3}}

Subtract the numbers:

12 - 6 = 6

= \frac{x ^{6} y ^{6}}{8 y ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{6}}{y ^{3}} = y^{6 - 3}

= \frac{x ^{6} y ^{6 - 3}}{8}

Subtract the numbers:

6 - 3 = 3

= \frac{x ^{6} y ^{3}}{8}

(6 x - 18)^{2} - 20 = - 25

y^{2} = 9

7 x + 15 = 3 (3 x - 7)

\frac{3}{4} - \frac{1}{3} z = \frac{1}{4}

- \frac{7}{2} + x = 2 x + \frac{1}{2}

What is ((2x^4y^2)/(4x^2y))^3 ?
The solution to ((2x^4y^2)/(4x^2y))^3 is (x^6y^3)/8