What is the answer to 2x+33+3x+20=104 ?

The answer to 2x+33+3x+20=104 is x= 51/5

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2x+33+3x+20=104

2 x + 33 + 3 x + 20 = 104

x = \frac{51}{5}

Decimal Notation

x = 10.2

Solution steps

2 x + 33 + 3 x + 20 = 104

Group like terms

2 x + 3 x + 33 + 20 = 104

Add similar elements:

2 x + 3 x = 5 x

5 x + 33 + 20 = 104

Add the numbers:

33 + 20 = 53

5 x + 53 = 104

Move

53

to the right side

5 x = 51

Divide both sides by

5

x = \frac{51}{5}

x^{2} - 6 x \geq 7

x^{3} - 2 x^{2} + 9 x - 18

6 (x + 3) - 4 = 5 (2 - x)

\frac{2 x + 1}{x} - \frac{x}{x + 2} \leq \frac{x ^{2} + 2 x + 4}{x ^{2} + 2 x}

\frac{1}{3 + 4 i}

What is the answer to 2x+33+3x+20=104 ?
The answer to 2x+33+3x+20=104 is x= 51/5
Solve for x: 2x+33+3x+20=104
The solution is x= 51/5