What are the solutions to the equation 15x^2-2x+1=0 ?

The solutions to the equation 15x^2-2x+1=0 are x= 1/15+i(sqrt(14))/(15),x= 1/15-i(sqrt(14))/(15)

Find the zeros of 15x^2-2x+1=0

The zeros of 15x^2-2x+1=0 are x= 1/15+i(sqrt(14))/(15),x= 1/15-i(sqrt(14))/(15)

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15 x^{2} - 2 x + 1 = 0

x = \frac{1}{15} + i \frac{14}{15}, x = \frac{1}{15} - i \frac{14}{15}

Solution steps

15 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 15 \cdot 1}{2 \cdot 15}

Simplify

(- 2)^{2} - 4 \cdot 15 \cdot 1 : 214 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 14 i}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 15}, x_{2} = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 15}

x = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 15} : \frac{1}{15} + i \frac{14}{15}

x = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 15} : \frac{1}{15} - i \frac{14}{15}

The solutions to the quadratic equation are:

x = \frac{1}{15} + i \frac{14}{15}, x = \frac{1}{15} - i \frac{14}{15}

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What are the solutions to the equation 15x^2-2x+1=0 ?
The solutions to the equation 15x^2-2x+1=0 are x= 1/15+i(sqrt(14))/(15),x= 1/15-i(sqrt(14))/(15)
Find the zeros of 15x^2-2x+1=0
The zeros of 15x^2-2x+1=0 are x= 1/15+i(sqrt(14))/(15),x= 1/15-i(sqrt(14))/(15)