What are the solutions to the equation 3x^2-7x-8=0 ?

The solutions to the equation 3x^2-7x-8=0 are x=(7+sqrt(145))/6 ,x=(7-sqrt(145))/6

Find the zeros of 3x^2-7x-8=0

The zeros of 3x^2-7x-8=0 are x=(7+sqrt(145))/6 ,x=(7-sqrt(145))/6

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3 x^{2} - 7 x - 8 = 0

x = \frac{7 + 145}{6}, x = \frac{7 - 145}{6}

Decimal Notation

x = 3.17359 \dots, x = - 0.84026 \dots

Solution steps

3 x^{2} - 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 8) = 145

x_{1, 2} = \frac{- ( - 7 ) \pm 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 145}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 145}{2 \cdot 3}

x = \frac{- ( - 7 ) + 145}{2 \cdot 3} : \frac{7 + 145}{6}

x = \frac{- ( - 7 ) - 145}{2 \cdot 3} : \frac{7 - 145}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 145}{6}, x = \frac{7 - 145}{6}

2 x^{2} - 6 x + 14 = 0

2 x + \frac{1}{4} > \frac{4}{9} x - 1

x^{2} + 2 x + 1 = 17

2 ∣ x - 3 ∣ - 3 > 15

x^{2} + 4 x + 10 = 0

What are the solutions to the equation 3x^2-7x-8=0 ?
The solutions to the equation 3x^2-7x-8=0 are x=(7+sqrt(145))/6 ,x=(7-sqrt(145))/6
Find the zeros of 3x^2-7x-8=0
The zeros of 3x^2-7x-8=0 are x=(7+sqrt(145))/6 ,x=(7-sqrt(145))/6