What are the solutions to the equation x(x+2)=1 ?

The solutions to the equation x(x+2)=1 are x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x(x+2)=1

The zeros of x(x+2)=1 are x=-1+sqrt(2),x=-1-sqrt(2)

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x (x + 2) = 1

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x (x + 2) = 1

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 1

Move

1

to the left side

x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

x = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

x = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

x = - 1 + 2, x = - 1 - 2

- \frac{1}{3} = \frac{j}{4} - \frac{10}{3}

3 x^{3} y + x^{2} y^{2}

3 x - \frac{3}{7} = \frac{7}{3}

20 x^{2} - 38 x^{3} - 30 x^{4}

4 \cdot 15

What are the solutions to the equation x(x+2)=1 ?
The solutions to the equation x(x+2)=1 are x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x(x+2)=1
The zeros of x(x+2)=1 are x=-1+sqrt(2),x=-1-sqrt(2)