What are the solutions to the equation 5x^2+x-2=0 ?

The solutions to the equation 5x^2+x-2=0 are x=(-1+sqrt(41))/(10),x=(-1-sqrt(41))/(10)

Find the zeros of 5x^2+x-2=0

The zeros of 5x^2+x-2=0 are x=(-1+sqrt(41))/(10),x=(-1-sqrt(41))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + x - 2 = 0

x = \frac{- 1 + 41}{10}, x = \frac{- 1 - 41}{10}

Decimal

x = 0.54031 \dots, x = - 0.74031 \dots

Solution steps

5 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 2) = 41

x_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 41}{2 \cdot 5}, x_{2} = \frac{- 1 - 41}{2 \cdot 5}

x = \frac{- 1 + 41}{2 \cdot 5} : \frac{- 1 + 41}{10}

x = \frac{- 1 - 41}{2 \cdot 5} : \frac{- 1 - 41}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 41}{10}, x = \frac{- 1 - 41}{10}

ln (5)

316 \cdot 332

5 x + 2 = x - 6

\frac{a ^{2} \cdot a ^{5}}{a ^{3}}

\frac{4}{9} \cdot 3

What are the solutions to the equation 5x^2+x-2=0 ?
The solutions to the equation 5x^2+x-2=0 are x=(-1+sqrt(41))/(10),x=(-1-sqrt(41))/(10)
Find the zeros of 5x^2+x-2=0
The zeros of 5x^2+x-2=0 are x=(-1+sqrt(41))/(10),x=(-1-sqrt(41))/(10)