What are the solutions to the equation x^2=5-x ?

The solutions to the equation x^2=5-x are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

Find the zeros of x^2=5-x

The zeros of x^2=5-x are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

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x^{2} = 5 - x

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

Decimal Notation

x = 1.79128 \dots, x = - 2.79128 \dots

Solution steps

x^{2} = 5 - x

Move

x

to the left side

x^{2} + x = 5

Move

5

to the left side

x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 5) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 1}, x_{2} = \frac{- 1 - 21}{2 \cdot 1}

x = \frac{- 1 + 21}{2 \cdot 1} : \frac{- 1 + 21}{2}

x = \frac{- 1 - 21}{2 \cdot 1} : \frac{- 1 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

6 x - x^{2} = 0

x^{2} - 23 x + 126

\frac{3}{8} π \cdot 81 + \frac{27}{2} = 27 (\frac{9}{8} π + 1)

5 d^{2} + 9 d + 5 = 3 d^{2}

What are the solutions to the equation x^2=5-x ?
The solutions to the equation x^2=5-x are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2
Find the zeros of x^2=5-x
The zeros of x^2=5-x are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2