What are the solutions to the equation 26=13x-7x^2 ?

The solutions to the equation 26=13x-7x^2 are x= 13/14-i(sqrt(559))/(14),x= 13/14+i(sqrt(559))/(14)

Find the zeros of 26=13x-7x^2

The zeros of 26=13x-7x^2 are x= 13/14-i(sqrt(559))/(14),x= 13/14+i(sqrt(559))/(14)

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26 = 13 x - 7 x^{2}

x = \frac{13}{14} - i \frac{559}{14}, x = \frac{13}{14} + i \frac{559}{14}

Solution steps

26 = 13 x - 7 x^{2}

Switch sides

13 x - 7 x^{2} = 26

Move

26

to the left side

13 x - 7 x^{2} - 26 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} + 13 x - 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 7 ) ( - 26 )}{2 ( - 7 )}

Simplify

1 3^{2} - 4 (- 7) (- 26) : 559 i

x_{1, 2} = \frac{- 13 \pm 559 i}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 13 + 559 i}{2 ( - 7 )}, x_{2} = \frac{- 13 - 559 i}{2 ( - 7 )}

x = \frac{- 13 + 559 i}{2 ( - 7 )} : \frac{13}{14} - i \frac{559}{14}

x = \frac{- 13 - 559 i}{2 ( - 7 )} : \frac{13}{14} + i \frac{559}{14}

The solutions to the quadratic equation are:

x = \frac{13}{14} - i \frac{559}{14}, x = \frac{13}{14} + i \frac{559}{14}

5 t^{2} - 50 t + 30 = 0

- 3 \leq 4 x < 12

\frac{( ( n + 1 ) ! ) ^{2}}{( n ! ) ^{2}}

2 x^{2} + 3 x = 42 - 2 x

2 x^{3} - 3 x^{2} - 2 x + 3

What are the solutions to the equation 26=13x-7x^2 ?
The solutions to the equation 26=13x-7x^2 are x= 13/14-i(sqrt(559))/(14),x= 13/14+i(sqrt(559))/(14)
Find the zeros of 26=13x-7x^2
The zeros of 26=13x-7x^2 are x= 13/14-i(sqrt(559))/(14),x= 13/14+i(sqrt(559))/(14)