What are the solutions to the equation u^2-2u-15=0 ?

The solutions to the equation u^2-2u-15=0 are u=5,u=-3

Find the zeros of u^2-2u-15=0

The zeros of u^2-2u-15=0 are u=5,u=-3

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u^{2} - 2 u - 15 = 0

u = 5, u = - 3

Solution steps

u^{2} - 2 u - 15 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

u_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, u_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

u = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

u = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

u = 5, u = - 3

(2 x^{5} y^{2})^{3}

∣ a - 6 ∣ = 3

2 (4 x - 3) \leq 5 x - 27

12 y^{3} + 26 y^{2} + 10 y

∣ x + 1 ∣ - ∣ x - 2 ∣ \geq 2

What are the solutions to the equation u^2-2u-15=0 ?
The solutions to the equation u^2-2u-15=0 are u=5,u=-3
Find the zeros of u^2-2u-15=0
The zeros of u^2-2u-15=0 are u=5,u=-3