What are the solutions to the equation r^2+5r+6=0 ?

The solutions to the equation r^2+5r+6=0 are r=-2,r=-3

Find the zeros of r^2+5r+6=0

The zeros of r^2+5r+6=0 are r=-2,r=-3

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r^{2} + 5 r + 6 = 0

r = - 2, r = - 3

Solution steps

r^{2} + 5 r + 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

r_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 5 + 1}{2 \cdot 1}, r_{2} = \frac{- 5 - 1}{2 \cdot 1}

r = \frac{- 5 + 1}{2 \cdot 1} : - 2

r = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

r = - 2, r = - 3

x^{2} = - 25

x + 4 = 12

\frac{x ^{- 2}}{x ^{- 4}}

2 e^{0}

x^{2} + 5 = 0

What are the solutions to the equation r^2+5r+6=0 ?
The solutions to the equation r^2+5r+6=0 are r=-2,r=-3
Find the zeros of r^2+5r+6=0
The zeros of r^2+5r+6=0 are r=-2,r=-3