What are the solutions to the equation (x+4)^2=-81 ?

The solutions to the equation (x+4)^2=-81 are x=9i-4,x=-9i-4

Find the zeros of (x+4)^2=-81

The zeros of (x+4)^2=-81 are x=9i-4,x=-9i-4

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(x + 4)^{2} = - 81

x = 9 i - 4, x = - 9 i - 4

Solution steps

(x + 4)^{2} = - 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 81 : x = 9 i - 4

Solve

x + 4 = - - 81 : x = - 9 i - 4

The solutions to the quadratic equation are:

x = 9 i - 4, x = - 9 i - 4

p^{2} - 14 p + 49

\frac{x - 6}{x + 3} \geq 0

(x - 3)^{2} < 0

\frac{a}{5} = \frac{a}{2} - 3

23 = 3 w + 5

What are the solutions to the equation (x+4)^2=-81 ?
The solutions to the equation (x+4)^2=-81 are x=9i-4,x=-9i-4
Find the zeros of (x+4)^2=-81
The zeros of (x+4)^2=-81 are x=9i-4,x=-9i-4