What are the solutions to the equation r^2-6r+9=0 ?

The solutions to the equation r^2-6r+9=0 are r=3

Find the zeros of r^2-6r+9=0

The zeros of r^2-6r+9=0 are r=3

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r^{2} - 6 r + 9 = 0

r = 3

Solution steps

r^{2} - 6 r + 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

r_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

r = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

r = 3

The solution to the quadratic equation is:

r = 3

- 10 < 5 x - 5 < 4 x - 2

- 3 < x - 10

121 \times 6 - 1

lo g_{7} (25)

\frac{x}{9} - 6 = 2

What are the solutions to the equation r^2-6r+9=0 ?
The solutions to the equation r^2-6r+9=0 are r=3
Find the zeros of r^2-6r+9=0
The zeros of r^2-6r+9=0 are r=3