What are the solutions to the equation 16x^2+7=12 ?

The solutions to the equation 16x^2+7=12 are x=(sqrt(5))/4 ,x=-(sqrt(5))/4

Find the zeros of 16x^2+7=12

The zeros of 16x^2+7=12 are x=(sqrt(5))/4 ,x=-(sqrt(5))/4

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16 x^{2} + 7 = 12

x = \frac{5}{4}, x = - \frac{5}{4}

Decimal Notation

x = 0.55901 \dots, x = - 0.55901 \dots

Solution steps

16 x^{2} + 7 = 12

Move

7

to the right side

16 x^{2} = 5

Divide both sides by

16

x^{2} = \frac{5}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{16}, x = - \frac{5}{16}

\frac{5}{16} = \frac{5}{4}

- \frac{5}{16} = - \frac{5}{4}

x = \frac{5}{4}, x = - \frac{5}{4}

∣ x + 9 ∣ = ∣ 9 - x ∣

x^{2} - x > 0

\frac{- x + 2}{x - 7} \geq 0

b^{2} - 8 b + 15

What are the solutions to the equation 16x^2+7=12 ?
The solutions to the equation 16x^2+7=12 are x=(sqrt(5))/4 ,x=-(sqrt(5))/4
Find the zeros of 16x^2+7=12
The zeros of 16x^2+7=12 are x=(sqrt(5))/4 ,x=-(sqrt(5))/4