What are the solutions to the equation p^2-10p+9=5 ?

The solutions to the equation p^2-10p+9=5 are p=5+sqrt(21),p=5-sqrt(21)

Find the zeros of p^2-10p+9=5

The zeros of p^2-10p+9=5 are p=5+sqrt(21),p=5-sqrt(21)

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p^{2} - 10 p + 9 = 5

p = 5 + 21, p = 5 - 21

Decimal Notation

p = 9.58257 \dots, p = 0.41742 \dots

Solution steps

p^{2} - 10 p + 9 = 5

Move

5

to the left side

p^{2} - 10 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 4 = 221

p_{1, 2} = \frac{- ( - 10 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 10 ) + 2 21}{2 \cdot 1}, p_{2} = \frac{- ( - 10 ) - 2 21}{2 \cdot 1}

p = \frac{- ( - 10 ) + 2 21}{2 \cdot 1} : 5 + 21

p = \frac{- ( - 10 ) - 2 21}{2 \cdot 1} : 5 - 21

The solutions to the quadratic equation are:

p = 5 + 21, p = 5 - 21

10 n^{2} = n^{2} + 16

x^{2} = - 75

2 w^{2} + w - 28 = 0

15 x^{3} (- 11 x^{2} y^{2})

2 z - 42 \geq 0

What are the solutions to the equation p^2-10p+9=5 ?
The solutions to the equation p^2-10p+9=5 are p=5+sqrt(21),p=5-sqrt(21)
Find the zeros of p^2-10p+9=5
The zeros of p^2-10p+9=5 are p=5+sqrt(21),p=5-sqrt(21)