What are the solutions to the equation 8=x^2-4 ?

The solutions to the equation 8=x^2-4 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 8=x^2-4

The zeros of 8=x^2-4 are x=2sqrt(3),x=-2sqrt(3)

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8 = x^{2} - 4

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

8 = x^{2} - 4

Switch sides

x^{2} - 4 = 8

Move

4

to the right side

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

4 x^{4} + 7 x^{2} - 2 = 0

- 4 (2 x - 6) = 10 x

10 m^{3} + 4 m^{2} - 90 m - 36

4 m^{2} - 4 mn + n^{2}

- x^{2} - 6 x + 16

What are the solutions to the equation 8=x^2-4 ?
The solutions to the equation 8=x^2-4 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 8=x^2-4
The zeros of 8=x^2-4 are x=2sqrt(3),x=-2sqrt(3)