What are the solutions to the equation 3x^2-2(x^2+4)=42 ?

The solutions to the equation 3x^2-2(x^2+4)=42 are x=5sqrt(2),x=-5sqrt(2)

Find the zeros of 3x^2-2(x^2+4)=42

The zeros of 3x^2-2(x^2+4)=42 are x=5sqrt(2),x=-5sqrt(2)

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3 x^{2} - 2 (x^{2} + 4) = 42

x = 52, x = - 52

Decimal Notation

x = 7.07106 \dots, x = - 7.07106 \dots

Solution steps

3 x^{2} - 2 (x^{2} + 4) = 42

Expand

- 2 (x^{2} + 4) : - 2 x^{2} - 8

3 x^{2} - 2 x^{2} - 8 = 42

Add similar elements:

3 x^{2} - 2 x^{2} = x^{2}

x^{2} - 8 = 42

Move

8

to the right side

x^{2} = 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 50, x = - 50

50 = 52

- 50 = - 52

x = 52, x = - 52

- 6 < 3 x - 7 < 11

(\frac{x ^{\frac{1}{3}}}{y ^{- \frac{2}{3}}})^{9}

x^{2} = - 3 x + 40

x^{4} - 10 x^{2} + 9 \geq 0

x + 4 = 20

What are the solutions to the equation 3x^2-2(x^2+4)=42 ?
The solutions to the equation 3x^2-2(x^2+4)=42 are x=5sqrt(2),x=-5sqrt(2)
Find the zeros of 3x^2-2(x^2+4)=42
The zeros of 3x^2-2(x^2+4)=42 are x=5sqrt(2),x=-5sqrt(2)