What is (x+1)/(x-2)>= x/(x-1) ?

The solution to (x+1)/(x-2)>= x/(x-1) is 1/2 2

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(x+1)/(x-2)>= x/(x-1)

\frac{x + 1}{x - 2} \geq \frac{x}{x - 1}

\frac{1}{2} \leq x < 1 or x > 2

Interval Notation

[\frac{1}{2}, 1) \cup (2, \infty)

Decimal Notation

0.5 \leq x < 1 or x > 2

Solution steps

\frac{x + 1}{x - 2} \geq \frac{x}{x - 1}

Rewrite in standard form

\frac{2 x - 1}{( x - 2 ) ( x - 1 )} \geq 0

Identify the intervals

\frac{1}{2} \leq x < 1 or x > 2

\frac{3}{16} + \frac{7}{16}

\frac{x + 9}{8} \geq 9

r^{2} + 6 r + 34 = 0

\frac{x}{4} = - 45

10 + x = - 6 x + 73

What is (x+1)/(x-2)>= x/(x-1) ?
The solution to (x+1)/(x-2)>= x/(x-1) is 1/2 <= x<1\lor x>2