What is the answer to 2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2 ?

The answer to 2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2 is x=-22/27

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2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2

2 (x - 1) - \frac{3 ( x + 1 )}{6} = 6 (x + 2) + 9 x - \frac{7}{2}

x = - \frac{22}{27}

Decimal Notation

x = - 0.81481 \dots

Solution steps

2 (x - 1) - \frac{3 ( x + 1 )}{6} = 6 (x + 2) + 9 x - \frac{7}{2}

Cancel

\frac{3 ( x + 1 )}{6} : \frac{x + 1}{2}

2 (x - 1) - \frac{x + 1}{2} = 6 (x + 2) + 9 x - \frac{7}{2}

Multiply both sides by

2

4 (x - 1) - (x + 1) = 12 (x + 2) + 18 x - 7

Expand

4 (x - 1) - (x + 1) : 3 x - 5

Expand

12 (x + 2) + 18 x - 7 : 30 x + 17

3 x - 5 = 30 x + 17

Move

5

to the right side

3 x = 30 x + 22

Move

30 x

to the left side

- 27 x = 22

Divide both sides by

- 27

x = - \frac{22}{27}

t^{4} - 10 t^{2} + 9 \leq 0

- 6 x + 39 = 7 x

3 x^{2} + 2 = 5 x

- 6 x^{2} = - 9 x + 7

\frac{2}{3} + \frac{1}{12}

What is the answer to 2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2 ?
The answer to 2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2 is x=-22/27
Solve for x: 2(x-1)-(3(x+1))/6 =6(x+2)+9x-7/2
The solution is x=-22/27