What are the solutions to the equation p^2+2p=0 ?

The solutions to the equation p^2+2p=0 are p=0,p=-2

Find the zeros of p^2+2p=0

The zeros of p^2+2p=0 are p=0,p=-2

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p^{2} + 2 p = 0

p = 0, p = - 2

Solution steps

p^{2} + 2 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

p_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 2 + 2}{2 \cdot 1}, p_{2} = \frac{- 2 - 2}{2 \cdot 1}

p = \frac{- 2 + 2}{2 \cdot 1} : 0

p = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

p = 0, p = - 2

\frac{- \frac{2}{2}}{\frac{2}{2}}

∣ 4 x - 8 ∣ \geq 3

10 x^{2} + 7 x = 0

5 x^{2} - 6 x - 27

2 \cdot 22

What are the solutions to the equation p^2+2p=0 ?
The solutions to the equation p^2+2p=0 are p=0,p=-2
Find the zeros of p^2+2p=0
The zeros of p^2+2p=0 are p=0,p=-2