What are the solutions to the equation v^2+5v-14=0 ?

The solutions to the equation v^2+5v-14=0 are v=2,v=-7

Find the zeros of v^2+5v-14=0

The zeros of v^2+5v-14=0 are v=2,v=-7

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v^{2} + 5 v - 14 = 0

v = 2, v = - 7

Solution steps

v^{2} + 5 v - 14 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

v_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 5 + 9}{2 \cdot 1}, v_{2} = \frac{- 5 - 9}{2 \cdot 1}

v = \frac{- 5 + 9}{2 \cdot 1} : 2

v = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

v = 2, v = - 7

\frac{2 k - 3}{- 5} > 7

- (\frac{4}{5})^{0}

\frac{4}{3} \cdot 5

5 - (- 4)

6 (x + 1) = 5 - 2 (6 x + 6)

What are the solutions to the equation v^2+5v-14=0 ?
The solutions to the equation v^2+5v-14=0 are v=2,v=-7
Find the zeros of v^2+5v-14=0
The zeros of v^2+5v-14=0 are v=2,v=-7