What are the solutions to the equation x^2+9x=10 ?

The solutions to the equation x^2+9x=10 are x=1,x=-10

Find the zeros of x^2+9x=10

The zeros of x^2+9x=10 are x=1,x=-10

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x^{2} + 9 x = 10

x = 1, x = - 10

Solution steps

x^{2} + 9 x = 10

Move

10

to the left side

x^{2} + 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 10) = 11

x_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 11}{2 \cdot 1}, x_{2} = \frac{- 9 - 11}{2 \cdot 1}

x = \frac{- 9 + 11}{2 \cdot 1} : 1

x = \frac{- 9 - 11}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 1, x = - 10

x^{8} y^{18}

8 x^{2} + 2 x - 6

\frac{1}{5} x < - 1 or 2 x > 0

- \frac{3}{4} x \geq - \frac{5}{12} + \frac{1}{3} x

5 x - \frac{2}{3} \leq 4 x - \frac{1}{5}

What are the solutions to the equation x^2+9x=10 ?
The solutions to the equation x^2+9x=10 are x=1,x=-10
Find the zeros of x^2+9x=10
The zeros of x^2+9x=10 are x=1,x=-10