What are the solutions to the equation 4x^2-12x+3=0 ?

The solutions to the equation 4x^2-12x+3=0 are x=(3+sqrt(6))/2 ,x=(3-sqrt(6))/2

Find the zeros of 4x^2-12x+3=0

The zeros of 4x^2-12x+3=0 are x=(3+sqrt(6))/2 ,x=(3-sqrt(6))/2

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4 x^{2} - 12 x + 3 = 0

x = \frac{3 + 6}{2}, x = \frac{3 - 6}{2}

Decimal Notation

x = 2.72474 \dots, x = 0.27525 \dots

Solution steps

4 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 3 = 46

x_{1, 2} = \frac{- ( - 12 ) \pm 4 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 6}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 4 6}{2 \cdot 4}

x = \frac{- ( - 12 ) + 4 6}{2 \cdot 4} : \frac{3 + 6}{2}

x = \frac{- ( - 12 ) - 4 6}{2 \cdot 4} : \frac{3 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 6}{2}, x = \frac{3 - 6}{2}

c = (3 (6) ln (6)) + 12

t r - 10 r + t n - 10 n

\frac{a}{3} - \frac{a}{5}

\frac{m}{- 5} \geq 2

y^{2} + 8 y - 20

What are the solutions to the equation 4x^2-12x+3=0 ?
The solutions to the equation 4x^2-12x+3=0 are x=(3+sqrt(6))/2 ,x=(3-sqrt(6))/2
Find the zeros of 4x^2-12x+3=0
The zeros of 4x^2-12x+3=0 are x=(3+sqrt(6))/2 ,x=(3-sqrt(6))/2