What is (-3xy^5)^2(x^3y)^{-1} ?

The solution to (-3xy^5)^2(x^3y)^{-1} is (9y^9)/x

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simplify (-3xy^5)^2(x^3y)^{-1}

simplify

(- 3 x y^{5})^{2} (x^{3} y)^{- 1}

\frac{9 y ^{9}}{x}

Solution steps

(- 3 x y^{5})^{2} (x^{3} y)^{- 1}

Simplify

(- 3 x y^{5})^{2} : 9 x^{2} y^{10}

= 9 x^{2} y^{10} (x^{3} y)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(x^{3} y)^{- 1} = \frac{1}{x ^{3} y}

= 9 x^{2} y^{10} \frac{1}{x ^{3} y}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{9 x ^{2} y ^{10} \cdot 1}{x ^{3} y}

Multiply the numbers:

9 \cdot 1 = 9

= \frac{9 x ^{2} y ^{10}}{x ^{3} y}

Simplify

\frac{y ^{10}}{y} : y^{9}

= \frac{9 x ^{2} y ^{9}}{x ^{3}}

Simplify

\frac{x ^{2}}{x ^{3}} : \frac{1}{x}

= \frac{9 y ^{9}}{x}

\frac{8 π}{180}

- 3 x^{2} + 33 x - 72

\frac{20}{45}

3 (x + 2) = 12

5 p - \frac{p}{7} = \frac{34 p}{7} + 3

What is (-3xy^5)^2(x^3y)^{-1} ?
The solution to (-3xy^5)^2(x^3y)^{-1} is (9y^9)/x