What are the solutions to the equation (t-1/2)^2=-73/4 ?

The solutions to the equation (t-1/2)^2=-73/4 are t= 1/2+i(sqrt(73))/2 ,t= 1/2-i(sqrt(73))/2

Find the zeros of (t-1/2)^2=-73/4

The zeros of (t-1/2)^2=-73/4 are t= 1/2+i(sqrt(73))/2 ,t= 1/2-i(sqrt(73))/2

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(t - \frac{1}{2})^{2} = - \frac{73}{4}

t = \frac{1}{2} + i \frac{73}{2}, t = \frac{1}{2} - i \frac{73}{2}

Solution steps

(t - \frac{1}{2})^{2} = - \frac{73}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - \frac{1}{2} = - \frac{73}{4} : t = \frac{1}{2} + i \frac{73}{2}

Solve

t - \frac{1}{2} = - - \frac{73}{4} : t = \frac{1}{2} - i \frac{73}{2}

The solutions to the quadratic equation are:

t = \frac{1}{2} + i \frac{73}{2}, t = \frac{1}{2} - i \frac{73}{2}

3.66 = (\frac{7281}{( 1000 ) + 7281}) (x)

45.3 \cdot \frac{1}{26.928}

- \frac{m}{12} = \frac{3}{5}

\frac{w}{2} - 1 > 1

ln (x - 2) \geq 0

What are the solutions to the equation (t-1/2)^2=-73/4 ?
The solutions to the equation (t-1/2)^2=-73/4 are t= 1/2+i(sqrt(73))/2 ,t= 1/2-i(sqrt(73))/2
Find the zeros of (t-1/2)^2=-73/4
The zeros of (t-1/2)^2=-73/4 are t= 1/2+i(sqrt(73))/2 ,t= 1/2-i(sqrt(73))/2