What are the solutions to the equation 5x^2-21x-20=0 ?

The solutions to the equation 5x^2-21x-20=0 are x=5,x=-4/5

Find the zeros of 5x^2-21x-20=0

The zeros of 5x^2-21x-20=0 are x=5,x=-4/5

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5 x^{2} - 21 x - 20 = 0

x = 5, x = - \frac{4}{5}

Decimal Notation

x = 5, x = - 0.8

Solution steps

5 x^{2} - 21 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

(- 21)^{2} - 4 \cdot 5 (- 20) = 29

x_{1, 2} = \frac{- ( - 21 ) \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 29}{2 \cdot 5}, x_{2} = \frac{- ( - 21 ) - 29}{2 \cdot 5}

x = \frac{- ( - 21 ) + 29}{2 \cdot 5} : 5

x = \frac{- ( - 21 ) - 29}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = 5, x = - \frac{4}{5}

\frac{9}{2} + 1

\frac{- 21}{- 3}

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) - 4 = 0

14 x^{2} y^{2} + 68 x y^{2} - 210 y^{2}

∣ 3 - 2 x ∣ = - 1

What are the solutions to the equation 5x^2-21x-20=0 ?
The solutions to the equation 5x^2-21x-20=0 are x=5,x=-4/5
Find the zeros of 5x^2-21x-20=0
The zeros of 5x^2-21x-20=0 are x=5,x=-4/5